2024 May 20 EAPCET Engineering afternoon Practice Test

Test Description

This EAPCET Engineering Practice Test was a previous year EAPCET exam conducted on 2024 May 20th Shift 2. This test consists of 160 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics (80), Physics (40) and Chemistry (40). The questions are given in the same format as in the exam conducted by Andhra Pradesh (AP) EAPCET exam in the year 2024.

This test is completely free, and students can attempt as many times as needed and help students in preparing for EAMCET entrance tests and get admissions into various reputed colleges for Engineering in the state of Andhra Pradesh.

Test Instructions

The test contains 160 multiple-choice questions.
Total time for the test is 3hrs 00m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 160)

f : ℝ \to ℝ

is defined by

f (x + y) = f (x) + 12 y,

\forall x, y \in ℝ

. If

f (1) = 6

, then

\sum_{r = 1}^{n} f (r) =

$n^{2}$
$5 n^{2}$
$6 n^{2}$
$\frac{3 n (n + 1)}{2}$

(2 of 160) The domain of the real valued function

f (x) = \sqrt{2 + x} + \sqrt{3 - x}

(-2, 3)
[-2, 3)
(-2, 3]
[-2, 3]

(3 of 160) If

2 . 4^{2 n + 1} + 3^{3 n + 1}

is divisible by

k

for all

n \in N

, then

k =

(4 of 160)

|\begin{matrix} a & b & c \\ a^{2} & b^{2} & c^{2} \\ 1 & 1 & 1 \end{matrix}|

is not equal to

$|\begin{matrix} a + 1 & b + 1 & c + 1 \\ a^{2} + 1 & b^{2} + 1 & c^{2} + 1 \\ 1 & 1 & 1 \end{matrix}|$
$|\begin{matrix} a - b & b - c & c \\ a^{2} - b^{2} & b^{2} - c^{2} & c^{2} \\ 0 & 0 & 1 \end{matrix}|$
$|\begin{matrix} a (a + 1) & b (b + 1) & c (c + 1) \\ a + 1 & b + 1 & c + 1 \\ - 1 & - 1 & - 1 \end{matrix}|$
$|\begin{matrix} a + b & b + c & c + a \\ a^{2} + b^{2} & b^{2} + c^{2} & c^{2} + a^{2} \\ 2 & 2 & 2 \end{matrix}|$

(5 of 160) Let A,B,C,D and E be

n \times n

matrices, each with non - zero determinant. If ABCDE = I, then

C^{- 1} =

$E^{- 1} D^{- 1} B^{- 1} A^{- 1}$
$D E A B$
$A^{- 1} B^{- 1} D^{- 1} E^{- 1}$
$A B D E$

(6 of 160) If

A = [a_{i j}], 1 \leq i, j \leq n

with

n \geq 2

and

a_{i j} = i + j

is a matrix, then the rank of A is

(7 of 160) If

z_{1} = 10 + 6 i

z_{2} = 4 + 6 i

and

z

is any complex number such that the argument of

\frac{(z - z_{1})}{(z - z_{2})}

\frac{π}{4}

, then

$|z - 7 - 9 i| = 3 \sqrt{2}$
$|z - 7 - 9 i| = 2 \sqrt{2}$
$|z - 3 + 9 i| = 3 \sqrt{2}$
$|z + 3 - 9 i| = 2 \sqrt{2}$

(8 of 160) If

\frac{3 - 2 i \sin θ}{1 + 2 i \sin θ}

is purely imaginary number, then

θ =

$2 n π \pm \frac{π}{4}$
$2 n π \pm \frac{π}{2}$
$n π \pm \frac{π}{3}$
$n π \pm \frac{π}{6}$

(9 of 160) If

z = x + i y

x^{2} + y^{2} = 1

and

z_{1} = z e^{i θ}

, then

\frac{z_{1}^{2 n} - 1}{z_{1}^{2 n} + 1} =

$- i \tan (n (θ + T a n^{- 1} (\frac{y}{x})))$
$i C o t (n (θ + T a n^{- 1} \frac{y}{x}))$
$i \tan (n (θ + T a n^{- 1} \frac{x}{y}))$
$i \tan (n (θ + T a n^{- 1} \frac{y}{x}))$

(10 of 160) Let

[r]

denote the largest integer not exceeding

r

and the roots of the equation

3 x^{2} + 6 x + 5 + α (x^{2} + 2 x + 2) = 0

are complex numbers whenever

α > L

and

α < M

. If

(L - M)

is minimum, then greatest value of

[r]

such that

L y^{2} + M y + r < 0

for all

y \in ℝ

L
M
L + M
M - L

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Test Details

Duration

3hrs 00m

Questions

160 Multiple Choice Questions

Passing Score

N/A% or higher to pass

Attempts

Unlimited attempts allowed

Total Runs

100

Test Description

Test Instructions

Quick Test

Practice Tests

Test Details

Duration

Questions

Passing Score

Attempts

Total Runs

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