2025 May 3rd EAMCET Engineering afternoon Practice Test

Test Description

This EAMCET Engineering Practice Test was a previous year EAMCET exam conducted on 2025 May 3rd shift 2. This test consists of 160 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics (80), Physics (40) and Chemistry (40). The questions are given in the same format as in the exam conducted by TELANGANA STATE (TS) EAMCET exam in the year 2025.

This test is completely free, and students can attempt as many times as needed and help students in preparing for EAMCET entrance tests and get admissions into various reputed colleges for Engineering in the state of Telangana.

Test Instructions

The test contains 160 multiple-choice questions.
Total time for the test is 3h 00m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 160) Let

f : R \to R

be defined by

f (x) = 5^{- |x|} + sgn (5^{- x})

, where

sgn x

denotes signum function of x. Then f is

one-one but not onto
onto but not one-one
both one-one and onto
neither one-one nor onto

(2 of 160) If the range of the real valued function

f (x) = \frac{x^{2} + x + k}{x^{2} - x + k}

[\frac{1}{3}, 3]

, then k=

-2
-1
1
2

(3 of 160) The value of the greatest integer k satisfying the inequation

2^{n + 4} + 12 \geq k (n + 4)

for all

n \in N

(4 of 160) If the system of simultaneous linear equations

x - 2 y + z = 0

2 x + 3 y + z = 6

and

x + 2 y + p z = q

has infinitely many solutions, then

$p + q = 4$
$p q = \frac{48}{49}$
$q - p = 3$
$\frac{p}{q} = 4$

(5 of 160) If the system of linear equations

(sin θ) x - y + z = 0

x - (cos θ) y + z = 0

x + y + (sin θ) z = 0

has non-trivial solution, then the least positive value of

θ

$\frac{π}{6}$
$\frac{π}{4}$
$\frac{π}{3}$
$\frac{π}{2}$

(6 of 160) If

A= [\begin{matrix} 1 & 2 & 3 \\ 2 & 1 & 1 \\ 1 & 3 & 1 \end{matrix}]

and

B= [\begin{matrix} 2 & 3 & 4 \\ 3 & 2 & 2 \\ 2 & 4 & 2 \end{matrix}]

, then

\sqrt{|Adj (AB)|} =

(7 of 160) If

A= [\begin{matrix} 1 & 5 & 2 \\ 4 & 1 & 3 \\ 2 & 6 & 3 \end{matrix}]

, then

|{(Adj A)}^{- 1}| =

-1
1
4
-4

(8 of 160) The amplitude of the complex number

\frac{(\sqrt{3} + i) (1 - \sqrt{3} i)}{(- 1 + i) (- 1 - i)}

$\frac{π}{2}$
$\frac{π}{3}$
$- \frac{5 π}{12}$
$- \frac{π}{6}$

(9 of 160) If a complex number z=x+iy represents a point P(x,y) in the Argand plane and z satisfies the condition that the imaginary part of

\frac{z - 3}{z + 3 i}

is zero, then the locus of the point P is

$x^{2} + y^{2} - 3 x + 3 y = 0$ , $(x, y) \neq (0, - 3)$
$2 x y - 3 x + 3 y + 9 = 0$ , $(x, y) \neq (0, - 3)$
$x - y - 3 = 0$ , $(x, y) \neq (0, - 3)$
$x + y + 3 = 0$ , $(x, y) \neq (0, - 3)$

(10 of 160)

{(\sqrt{3} + i)}^{10} + {(\sqrt{3} - i)}^{10} =

$1024 \sqrt{3}$
1024
2048
$512 \sqrt{3}$

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Test Details

Duration

3h 00m

Questions

160 Multiple Choice Questions

Passing Score

N/A% or higher to pass

Attempts

Unlimited attempts allowed

Total Runs

100