2025 May 4th EAMCET Engineering forenoon Practice Test

Test Description

This EAMCET Engineering Practice Test was a previous year EAMCET exam conducted on 2025 May 4th shift 2. This test consists of 160 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics (80), Physics (40) and Chemistry (40). The questions are given in the same format as in the exam conducted by TELANGANA STATE (TS) EAMCET exam in the year 2025.

This test is completely free, and students can attempt as many times as needed and help students in preparing for EAMCET entrance tests and get admissions into various reputed colleges for Engineering in the state of Telangana.

Test Instructions

The test contains 160 multiple-choice questions.
Total time for the test is 3h 00m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 160) If

f (x) = x^{2} + bx + c

and

f (1 + k) = f (1 - k) \forall K \in R

, for two real numbers b and c, then

f(1) < f(0) < f(-1)
f(-1) < f(0) < f(1)
f(0) < f(-1) < f(1)
f(0) < f(1) < f(-1)

(2 of 160) The domain of the real valued function

f (x) = l o g_{\sqrt{2}} (\sqrt{x^{2} + x} + \sqrt{x^{2} - x})

[-1, 1]
$(- \infty, - 1] \cup [1, \infty)$
$(- \infty, \infty)$
$(0, \infty)$

(3 of 160)

t_{1}, t_{2}, t_{3} . . . t_{n}

are positive integers,

S_{n} = t_{1} + t_{2} + t_{3} + . . . + t_{n}

S_{1} = 1^{2}, S_{2} = 3^{2}, S_{3} = 6^{2}, S_{4} = 10^{2}, S_{5} = 15^{2}

and similarity other terms are there. Following this pattern, if

S_{10} = k^{2}

then k=

(4 of 160) If

x = α

y = β

z = γ

is the solution of the system of equations 2x+3y+z=-1, 3x+y+z=4, x-3y-2z=1, then the value of

β

-2
-1
2
1

(5 of 160) The positive value of 'a' for which the system of linear homogeneous equations x+ay+z=0, ax+2y-z=0, 2x+3y+z=0 has non-trivial solutions is

0
1
$\frac{1 + \sqrt{5}}{2}$
$\frac{\sqrt{5} - 1}{2}$

(6 of 160) If

A = [\begin{matrix} 1 & 2 & 2 \\ 2 & 1 & 1 \\ 1 & 2 & 1 \end{matrix}]

, then

|Adj (A^{2})| =

(7 of 160)

K = |\begin{matrix} 3 & 4 \\ 5 & 4 \end{matrix}| + |\begin{matrix} 1 & - 1 \\ 5 & 4 \end{matrix}| + |\begin{matrix} \frac{1}{3} & \frac{1}{4} \\ 5 & 4 \end{matrix}| + |\begin{matrix} \frac{1}{9} & - \frac{1}{16} \\ 5 & 4 \end{matrix}| + . . .

\infty

then K=

(8 of 160)

{(\frac{1 + i}{l - i})}^{228} =

-4 ${(\frac{1 - i}{1 + i})}^{226}$
4 ${(\frac{1 - i}{1 + i})}^{226}$
${(\frac{1 - i}{1 + i})}^{228}$
- ${(\frac{1 - i}{1 + i})}^{228}$

(9 of 160) Let z=x+iy represent a point P(x, y) in the Argand plane. If z satisfies the condition that amplitude of

\frac{z - 3}{z - 2 i} = - \frac{π}{2}

, then the locus of P is

the circle $x^{2} + y^{2} - 3 x - 2 y = 0$
the are of the circle $x^{2} + y^{2} - 3 x - 2 y = 0$ intercepted by the diameter 2x+3y-6=0 not containing the origin and excluding the points (3, 0) and (0, 2)
The arc of the circle $x^{2} + y^{2} - 3 x - 2 y = 0$ intercepted by the diameter 2x+3y-6=0 not containing the origin and excluding the points (3, 0) and (0, 2)
the circle $x^{2} + y^{2} - 3 x - 2 y = 0$ not containing the point (0, 2)